Answer: B
The CHX2 between the two carbonyls is deprotonated and alkylated twice, giving CHX3CO−C(CHX3)(CX2HX5)−COOEt. Hydrolysis and acidification give the beta-keto acid, which loses COX2 on warming. The remaining CHX3CO−CH(CHX3)(CX2HX5) is 3-methylpentan-2-one.