Answer: A
Protonation and loss of water from one OH gives the tertiary cation (CHX3)X2CX+−C(CHX3)X2OH. A methyl group migrates from the carbinol carbon to the cationic carbon, giving the oxocarbenium ion (CHX3)X3C−CX+(CHX3)−OH. Loss of HX+ from OH gives (CHX3)X3C−CO−CHX3.