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JEE Advanced levelOne or more correct optionsDifficulty 3 of 3g2208

For butan-2-one, $CH X_{3} COCH X_{2} CH X_{3}$ , which statements are correct?

AIt has 5 alpha hydrogens
BIt forms two constitutionally different enols
COne of its enols shows geometrical isomerism
DIt forms only one enol because the two alpha carbons are equivalent

Answer: A, B, C

Alpha hydrogens:

3 + 2 = 5

(A). Enolisation at

CH X_{3}

or

CH X_{2}

gives two different enols (B). Only

CH X_{3} C (OH) = CHCH X_{3}

has a double bond with different groups on both carbons, so it has E and Z forms (C). The alpha carbons are not equivalent, so (D) is wrong.

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