Answer: D
The alcohol shown is 3-methylbutan-2-ol. Loss of water gives a secondary cation, which undergoes a hydride shift to the tertiary cation. Loss of a proton gives the most substituted alkene, 2-methylbut-2-ene, in which three CH3 groups are attached to the sp2 carbons. That gives 3 x 3 = 9 hydrogens (checked with RDKit).