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JEE Main levelOne or more correct optionsDifficulty 2 of 3g1210

Which of the following statements about the geometry of the central carbon are correct?

A $CH X_{3}^{∙}$ is planar with the unpaired electron in a p orbital
B $(CH X_{3}) X_{3} C X^{-}$ is planar and sp2 hybridised
C $(CH X_{3}) X_{3} C X^{+}$ is trigonal planar and sp2 hybridised
D $CH X_{3} X^{-}$ is pyramidal and sp3 hybridised

Answer: A, C, D

A carbocation has three sigma bonds and an empty p orbital (planar). The methyl radical has three sigma bonds and one electron in a p orbital (planar). A carbanion has three bonds and a lone pair, which is pyramidal sp3 like ammonia, so the last statement is wrong.

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