JEE Advanced levelOne or more correct optionsDifficulty 3 of 3eq219
A water sample contains 60.0mg of CaX2+ and 24.0mg of MgX2+ per litre (Ca=40, Mg=24, CaCOX3=100). A 100.0mL portion is titrated with 0.0100M EDTA. At pH 10 both ions react; at pH 12, Mg(OH)X2 precipitates and only CaX2+ reacts. Which statements are correct?
ATotal hardness is 250ppm as CaCOX3.
BThe hardness due to MgX2+ is 100ppm as CaCOX3.
CThe CaX2+ accounts for 40\% of the total hardness.
DAt pH 12 the EDTA volume needed for the 100.0mL portion is 15.0mL.
Answer: A, B, D
CaX2+=60.0/40=1.50 mmol/L and MgX2+=24.0/24=1.00 mmol/L, i.e. 150 and 100 ppm as CaCOX3, total 250 ppm. 100.0mL has 0.150 mmol Ca, needing 0.150/0.0100=15.0mL EDTA at pH 12 (25.0 mL at pH 10). Ca contributes 150/250=60%, not 40%.