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MolSynapse / Question bank / Equivalent Concept and Titration / Acid-base titrations and double titration (NaOH, Na2CO3, NaHCO3)

NEET levelSingle correct optionDifficulty 1 of 3eq118

25.0 mL of 0.100 M $Na X_{2} CO X_{3}$ is titrated with 0.100 M HCl using methyl orange (end point = complete conversion to $CO X_{2}$ ). The volume of HCl needed is:

A $25.0 mL$
B $12.5 mL$
C $100.0 mL$
D $50.0 mL$

Answer: D

At the methyl orange end point

CO X_{3} X^{2 -}

takes 2

H X^{+}

, so n-factor = 2.

meq

of carbonate

= 0.100 \times 25.0 \times 2 = 5.00

; HCl volume = 5.00/0.100 = 50.0 mL.

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