Answer: A, B, C
Permanganate = 20.0 x 0.0400 = 0.80 mmol; oxalate left = 2.5 x 0.80 = 2.00 mmol. Oxalate taken = 5.00 mmol, so consumed (= MnO2) = 3.00 mmol. Mass MnO2 = 3.00 x 87 = 261 mg; percent = 261/400 x 100 = 65.25%. The permanganate step consumes only 2.00 mmol of oxalate, not 4.00.