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JEE Advanced levelNumerical answerDifficulty 3 of 3eq103

of water containing only and as alkalinity is titrated with . The phenolphthalein end point () is reached at and the methyl orange end point (total, all carbonate species to ) at from the start. Taking the molar mass of as , find the originally present in mg/L (nearest integer).

Numerical answer type, answer in mg/L, tolerance 1.

Answer: 168 mg/L

Carbonate consumes 3.0 mL to reach phenolphthalein end and another 3.0 mL to reach methyl orange, i.e. 6.0 mL in all. Original bicarbonate needs 11.0 - 6.0 = 5.0 mL = 0.100 mmol in 50.0 mL. Mass = 0.100 mmol x 84 = 8.40 mg per 0.0500 L = 168 mg/L.
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