JEE Advanced levelSingle correct optionDifficulty 3 of 3eq088
25.0mL of 0.100MNaX2SX2OX3 needs 25.0mL of 0.0500M iodine solution (SX2OX3X2− goes to SX4OX6X2−). If the same amount of thiosulphate is instead oxidised completely to sulphate (SX2OX3X2−+4ClX2+5HX2O2SOX4X2−+8ClX−+10HX+) by 0.0500MClX2 water, the volume of chlorine water needed is
A50 mL
B400 mL
C25 mL
D200 mL
Answer: D
mol thiosulphate = 0.0250 x 0.100 = 2.50e-3. With Cl2, 4 mol Cl2 per mol thiosulphate (8 electrons), so mol Cl2 = 1.00e-2. Volume = 1.00e-2/0.0500 = 200 mL. (With iodine only 0.5 mol I2 per mol, giving 25 mL, as stated.)