Answer: A, B, D
Since V1=14.0>V2=6.0, the sample is NaOH+NaX2COX3. NaX2COX3=0.100×6.0=0.60 mmol; NaOH=0.100×(14.0−6.0)=0.80 mmol. Total HCl=0.100×20.0=2.00 mmol =NaOH+2NaX2COX3=0.80+1.20. NaHCOX3 cannot coexist with NaOH, so option 3 is false.