JEE Advanced levelSingle correct optionDifficulty 3 of 3ev151
In a COD test, a sample consumes 1.20mmol of KX2CrX2OX7 per litre. Take 1 mol of KX2CrX2OX7 as equivalent to 1.5 mol of OX2 (O = 16). The COD of the sample is:
A57.6mgL−1
B115.2mgL−1
C38.4mgL−1
D28.8mgL−1
Answer: A
Oxygen equivalent = 1.20×1.5=1.80 mmol of OX2 per litre. Mass = 1.80×32=57.6 mg/L. Using 1 mol of OX2 per mol of dichromate gives 38.4, and 3 mol gives 115.2.