A galvanic cell with n = 2 has E deg = 0.46 V at 298 K and temperature coefficient ((partial E deg)/(partial T))_P = -1.0x 10^-4 V K^-1. The standard enthalpy change of the cell reaction, in kJ mol^-1 (one decimal), is.

JEE Advanced levelNumerical answerDifficulty 3 of 3ec20

A galvanic cell with $n = 2$ has $E^{\circ} = 0.46 V$ at 298 K and temperature coefficient $(\frac{\partial E ^{\circ}}{\partial T})_{P} = - 1.0 \times 1 0^{- 4} V K^{- 1}$ . The standard enthalpy change of the cell reaction, in $kJ mo l^{- 1}$ (one decimal), is.

Numerical answer type, answer in kJ/mol, tolerance 0.2.

Δ G^{\circ} = - n F E^{\circ} = - 2 \times 96500 \times 0.46 = - 88780 J

Δ S^{\circ} = n F (\frac{\partial E ^{\circ}}{\partial T}) = 2 \times 96500 \times (- 1.0 \times 1 0^{- 4}) = - 19.3 J K^{- 1}

Δ H^{\circ} = Δ G^{\circ} + T Δ S^{\circ} = - 88780 + 298 \times (- 19.3) = - 94531 J = - 94.5 kJ mo l^{- 1}