The conductivity of a 0.020 M solution of an electrolyte is 3.6x 10^-3 S cm^-1. Its molar conductivity in S cm^2 mol^-1 is

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The conductivity of a $0.020 M$ solution of an electrolyte is $3.6 \times 1 0^{- 3} S c m^{- 1}$ . Its molar conductivity in $S c m^{2} mo l^{- 1}$ is

With

κ

S c m^{- 1}

and

c

mol L^{- 1}

Λ_{m} = \frac{1000 κ}{c}

Λ_{m} = \frac{1000 \times 3.6 \times 1 0 ^{- 3}}{0.020} = 180 S c m^{2} mo l^{- 1}

. Omitting the factor 1000 gives

0.18

; multiplying

κ

c

gives

7.2 \times 1 0^{- 5}