A copper concentration cell is built as follows. The right compartment contains 0.50 M CuSO4. The left compartment is prepared by mixing 20 mL of 0.50 M CuSO4 with 980 mL of water. Both have copper electrodes. The cell EMF at 298 K in mV is (nearest integer; take 2.303RT/F = 0.0591 V, log 5 = 0.699).

JEE Advanced levelNumerical answerDifficulty 3 of 3ec095

A copper concentration cell is built as follows. The right compartment contains $0.50 M$ $CuSO X_{4}$ . The left compartment is prepared by mixing $20 mL$ of $0.50 M$ $CuSO X_{4}$ with $980 mL$ of water. Both have copper electrodes. The cell EMF at 298 K in mV is (nearest integer; take $2.303 RT / F = 0.0591 V$ , $lo g 5 = 0.699$ ).

Numerical answer type, answer in mV, tolerance 1.

Left concentration:

0.50 \times \frac{20}{1000} = 0.010 M

, a 50-fold dilution. The dilute side is the anode.

E = \frac{0.0591}{2} lo g \frac{0.50}{0.010} = 0.02955 \times lo g 50 = 0.02955 \times 1.699 = 0.0502 V \approx 50 mV