Answer: A
ΔrG∘=−2×96500×0.100=−19300 J. ΔrS∘=2×96500×4.0×10−4=77.2 JK−1. ΔrH∘=ΔrG∘+TΔrS∘=−19300+298×77.2=−19300+23005.6=+3705.6 J=+3.71 kJ. The reaction is endothermic yet ΔrG∘<0 because TΔrS∘ dominates. Option C results from subtracting TΔS instead of adding; option D ignores entropy.