Answer: A, C, D
A: for E∘(MXn+/M)<0, the cell M ∣ MXn+ ∣∣ HX+ ∣ HX2 has positive EMF, so hydrogen evolution is thermodynamically allowed (kinetics may be slow, e.g. Pb). B is reversed: a more positive E∘ means a stronger oxidising MX+ and a weaker reducing M. C: 2.87>1.36>1.09>0.54 V gives the stated order. D: the small LiX+ ion is strongly hydrated, which more than compensates its higher ionisation enthalpy, giving E∘=−3.05 V versus −2.71 V for Na.