A Daniell cell $Zn ∣ Zn X^{2 +} (1 M) ∣∣ Cu X^{2 +} (1 M) ∣ Cu$ has $E_{cell}^{\circ} = 1.10 V$ . Assuming the EMF stays at $1.10 V$ , the maximum electrical work (in J, nearest integer) obtainable when $0.010 mol$ of Zn dissolves is (take $F = 96500 C mo l^{- 1}$ ).

Numerical answer type, answer in J, tolerance 1.

Answer: 2123 J

Maximum work

= n FE

where

n

is the number of moles of electrons passed. Each Zn gives 2 electrons, so

n = 2 \times 0.010 = 0.020 mol

. Charge

= 0.020 \times 96500 = 1930 C

. Work

= 1930 \times 1.10 = 2123 J