When excess aqueous ammonia is added to pale blue aqueous Cu^2+, a deep blue solution of [Cu(NH3)4]^2+ forms. The absorp

Question

When excess aqueous ammonia is added to pale blue aqueous Cu^2+, a deep blue solution of [Cu(NH3)4]^2+ forms. The absorption maximum shifts to a shorter wavelength because:

Accepted Answer

NH3 is a stronger-field ligand than H2O, so the d-orbital splitting increases

Answer

the number of unpaired electrons in copper changes from 1 to 0

Answer

the oxidation state of copper changes from +2 to +3

Answer

NH3 is a weaker-field ligand than H2O, so the splitting decreases

When excess aqueous ammonia is added to pale blue aqueous $Cu X^{2 +}$ , a deep blue solution of $[Cu (NH X_{3}) X_{4}] X^{2 +}$ forms. The absorption maximum shifts to a shorter wavelength because:

Answer: A

More questions on Colour and magnetic properties

When excess aqueous ammonia is added to pale blue aqueous CuX2+, a deep blue solution of [Cu(NHX3​)X4​]X2+ forms. The absorption maximum shifts to a shorter wavelength because:

Answer: A

More questions on Colour and magnetic properties

When excess aqueous ammonia is added to pale blue aqueous $Cu X^{2 +}$ , a deep blue solution of $[Cu (NH X_{3}) X_{4}] X^{2 +}$ forms. The absorption maximum shifts to a shorter wavelength because: