JEE Main levelSingle correct optionDifficulty 2 of 3df097
In acidic medium, KMnOX4 reacts with HX2OX2 as 2MnOX4X−+5HX2OX2+6HX+→2MnX2++5OX2+8HX2O. The number of moles of OX2 released per mole of KMnOX4 is
A5
B1.5
C1
D2.5
Answer: D
From the balanced equation, 2 mol MnOX4X− release 5 mol OX2, so 5/2=2.5 mol OX2 per mol of permanganate. Here HX2OX2 acts as the reducing agent.