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JEE Main levelSingle correct optionDifficulty 2 of 3df089

When $KMnO X_{4}$ oxidises potassium iodide in a neutral or weakly alkaline medium, the iodine-containing product is

A $I X_{2}$
B $IO X_{3} X^{-}$
C $IO X^{-}$
D $IO X_{4} X^{-}$

Answer: B

In neutral or weakly alkaline medium

MnO X_{4} X^{-}

is reduced to

MnO X_{2}

and iodide is oxidised to iodate:

2 MnO X_{4} X^{-} + I X^{-} + H X_{2} O \to 2 MnO X_{2} + IO X_{3} X^{-} + 2 OH X^{-}

. In acid solution iodine (

I X_{2}

) is obtained.

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