Answer: A, B, C
CuX+→CuX2++Cu (Ecell∘=+0.36 V); 3MnOX4X2−+4HX+→2MnOX4X−+MnOX2+2HX2O; 2MnX3++2HX2O→MnX2++MnOX2+4HX+. FeX3+ is stable because there is no intermediate state to which it can both reduce and oxidise spontaneously (FeX4+ is not accessible in water).