Given E deg(Br2/Br^-) = +1.09 V, E deg(I2/I^-) = +0.54 V, E deg(Sn^4+/Sn^2+) = +0.15 V, E deg(Cu^2+/Cu) = +0.34 V and E deg(Fe^3+/Fe^2+) = +0.77 V, which species can oxidise Fe^2+ to Fe^3+ under standard conditions?

JEE Main levelSingle correct optionDifficulty 2 of 3df070

Given $E^{\circ} (Br X_{2} / Br X^{-}) = + 1.09 V$ , $E^{\circ} (I X_{2} / I X^{-}) = + 0.54 V$ , $E^{\circ} (Sn X^{4 +} / Sn X^{2 +}) = + 0.15 V$ , $E^{\circ} (Cu X^{2 +} / Cu) = + 0.34 V$ and $E^{\circ} (Fe X^{3 +} / Fe X^{2 +}) = + 0.77 V$ , which species can oxidise $Fe X^{2 +}$ to $Fe X^{3 +}$ under standard conditions?

An oxidant must have a reduction potential higher than

+ 0.77 V

. Only

Br X_{2}

(

1.09 V

) qualifies;

I X_{2}

(

0.54

Sn X^{4 +}

(

0.15

) and

Cu X^{2 +}

(

0.34

) are all lower.