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JEE Advanced levelOne or more correct optionsDifficulty 3 of 3cc214

Consider the tetrahedral carbonyls $Ni (CO) X_{4}$ , $[Co (CO) X_{4}] X^{-}$ and $[Fe (CO) X_{4}] X^{2 -}$ . Which statements are correct?

AAll three are isoelectronic (36 electrons)
BAll three are tetrahedral
COxidation state of the metal is $0$ in all three
DAll three are diamagnetic

Answer: A, B, D

Total electrons: Ni

28 + 8 = 36

, Co

^{-}

27 + 1 + 8 = 36

, Fe

^{2 -}

26 + 2 + 8 = 36

, so they are isoelectronic (A) and all tetrahedral (B), diamagnetic (D). Oxidation states are

0

,

- 1

,

- 2

so (C) is false. Correct: A, B, D.

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