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NEET levelSingle correct optionDifficulty 1 of 3cc172

Nickel tetracarbonyl, $Ni (CO) X_{4}$ , has which geometry and hybridisation at nickel?

Asquare planar, $d s p^{2}$
Boctahedral, $d^{2} s p^{3}$
Ctetrahedral, $s p^{3}$
Dtrigonal bipyramidal, $d s p^{3}$

Answer: C

Ni(0) is

3 d^{10}

with full

3 d

orbitals. The four

CO

ligands donate into the

4 s

and three

4 p

orbitals, giving

s p^{3}

hybridisation. The shape is tetrahedral and the molecule is diamagnetic.

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