JEE Main levelSingle correct optionDifficulty 2 of 3cc101
Match each complex in Column I with its number of unpaired electrons in Column II (H2O is weak field, CN- is strong field).
Column I: P [Fe(HX2O)X6]X2+; Q [Fe(CN)X6]X4−; R [Cr(HX2O)X6]X3+; S [Cu(NHX3)X4]X2+.
Column II: 1 zero; 2 one; 3 three; 4 four.
AP-4, Q-1, R-3, S-2
BP-4, Q-1, R-2, S-3
CP-3, Q-1, R-4, S-2
DP-4, Q-2, R-3, S-1
Answer: A
P: FeX2+ is d6 high spin, 4 unpaired. Q: d6 low spin, 0. R: CrX3+ is d3, 3. S: CuX2+ is d9, 1.