NEET levelSingle correct optionDifficulty 1 of 3cc092
The number of unpaired electrons in the high-spin octahedral ion [Fe(HX2O)X6]X3+ is
A1
B0
C3
D5
Answer: D
Fe is in the +3 state, so the ion is 3d5. In a high-spin octahedral field the five electrons occupy t2g3eg2, all unpaired. The number of unpaired electrons is 5.