Using CFSE =(-0.4 n_t_2g+0.6 n_e_g)Delta_o (pairing energy ignored; H2O weak field, NH3 on Co(III) low spin), which statements are correct?

CFSE of [Fe(H2O)6]^2+ is -0.4 Delta_o.

CFSE of [V(H2O)6]^3+ is -0.8 Delta_o.

CFSE of [Co(NH3)6]^3+ is -1.6 Delta_o.

CFSE of [Fe(H2O)6]^2+ is -0.4 Delta_o.

CFSE of [V(H2O)6]^3+ is -0.8 Delta_o.

JEE Advanced levelOne or more correct optionsDifficulty 3 of 3cc045

Using CFSE $= (- 0.4 n_{t_{2 g}} + 0.6 n_{e_{g}}) Δ_{o}$ (pairing energy ignored; $H X_{2} O$ weak field, $NH X_{3}$ on Co(III) low spin), which statements are correct?

Mn(II) high spin

d^{5}

t_{2 g}^{3} e_{g}^{2}

gives

0

. Co(III) low spin

d^{6}

t_{2 g}^{6}

gives

- 2.4 Δ_{o}

, so statement 2 is false. Fe(II) high spin

d^{6}

t_{2 g}^{4} e_{g}^{2}

gives

- 1.6 + 1.2 = - 0.4 Δ_{o}

. V(III) is

d^{2}

t_{2 g}^{2}

gives

- 0.8 Δ_{o}