The compound $[Pt (NH X_{3}) X_{4} Cl X_{2}] Cl X_{2}$ is an octahedral Pt(IV) complex. When $0.010$ mol of it is treated with excess aqueous $AgNO X_{3}$ (Ag $= 108$ , Cl $= 35.5$ ), the mass of $AgCl$ precipitated is

Answer: C

Only the two chlorides outside the coordination sphere are precipitated. Moles of AgCl

= 2 \times 0.010 = 0.020

mol. Molar mass of AgCl

= 108 + 35.5 = 143.5

g/mol, so mass

= 0.020 \times 143.5 = 2.87