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JEE Main levelSingle correct optionDifficulty 2 of 3el176

Sodium lauryl sulphate is prepared in the laboratory by the following sequence:

Adodecan-1-ol, oxidised with acidified $K X_{2} Cr X_{2} O X_{7}$ , then treated with NaOH
Bdodecanoic acid, treated with NaOH, then with conc. $H X_{2} SO X_{4}$
Cdodecan-1-ol, treated with conc. $H X_{2} SO X_{4}$ , then neutralised with aqueous NaOH
Dbenzene, treated with dodecene, then with NaOH

Answer: C

Esterification of lauryl alcohol with sulphuric acid gives lauryl hydrogen sulphate,

C X_{12} H X_{25} OH + H X_{2} SO X_{4} C X_{12} H X_{25} OSO X_{3} H + H X_{2} O

. Neutralising with NaOH gives

C X_{12} H X_{25} OSO X_{3} Na

. The other routes give soap or other products.

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