Numerical answer type, answer in g, tolerance 0.5.
Answer: 551 g
Moles per litre: Ca2+ = 0.096/40 = 0.0024 mol and Mg2+ = 0.0288/24 = 0.0012 mol, total 0.0036 mol of divalent ions. Stearate needed = 2 x 0.0036 = 0.00720 mol per litre. For 250 L the mass is 0.00720 x 250 x 306 = 550.8 g, about 551 g.