A undergoes parallel first-order reactions A -> B (k_1 = 3.0x10^-2 min^-1) and A -> C (k_2 = 1.0x10^-2 min^-1). Use ln 2 = 0.693. Select the correct statement(s).

The half-life of A is 17.3 min.

[B]/[C] = 3 at every time during the reaction.

After one half-life of A, [B] = 0.50[A]_0.

Finally one-third of the A is converted to C.

The half-life of A is 17.3 min.

[B]/[C] = 3 at every time during the reaction.

JEE Main levelOne or more correct optionsDifficulty 2 of 3ck216

A undergoes parallel first-order reactions $A B$ ( $k_{1} = 3.0 \times 1 0^{- 2} mi n^{- 1}$ ) and $A C$ ( $k_{2} = 1.0 \times 1 0^{- 2} mi n^{- 1}$ ). Use $ln 2 = 0.693$ . Select the correct statement(s).

Total

k = 4.0 \times 1 0^{- 2}

t_{1/2} = 0.693/0.04 = 17.3

min. Both products form from the same

[A]

, so

[B] / [C] = k_{1} / k_{2} = 3

always. After one half-life, half of A has reacted and B has received

\frac{3}{4}

of that, i.e.

0.375 [A]_{0}

, not

0.50

. The final share of C is

k_{2} / k = 0.25

, not one-third.