For 2A -> 3B, the concentration of A changes from 0.600 M to 0.420 M in 75 s. Taking the rate of reaction as -(1)/(2)Delta[A]/Delta t, find its value in units of 10^-3 M s^-1 (answer to two decimal places).

JEE Main levelNumerical answerDifficulty 2 of 3ck213

For $2 A 3 B$ , the concentration of A changes from $0.600 M$ to $0.420 M$ in $75 s$ . Taking the rate of reaction as $- \frac{1}{2} Δ [A] /Δ t$ , find its value in units of $1 0^{- 3} M s^{- 1}$ (answer to two decimal places).

Numerical answer type, answer in 1e-3 M/s, tolerance 0.01.

Rate of reaction

= - \frac{1}{2} Δ [A] /Δ t

. With

Δ [A] = - 0.180 M

over

75 s

: rate

= \frac{1}{2} \times \frac{0.180}{75} = 0.0012 M s^{- 1} = 1.20 \times 1 0^{- 3} M s^{- 1}