For A B with first-order rate constants k_f = 2.0x10^-2 s^-1 and k_b = 5.0x10^-3 s^-1, the equilibrium constant is

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For $A B$ with first-order rate constants $k_{f} = 2.0 \times 1 0^{- 2} s^{- 1}$ and $k_{b} = 5.0 \times 1 0^{- 3} s^{- 1}$ , the equilibrium constant is

At equilibrium the forward and backward rates are equal,

k_{f} [A] = k_{b} [B]

, so

K = [B] / [A] = k_{f} / k_{b} = 2.0 \times 1 0^{- 2} /5.0 \times 1 0^{- 3} = 4.0