Answer: A, B, D
With equal A, kB/kC=exp[−(E1−E2)/RT]: it is 3.29×10−4 at 300 K and 0.090 at 1000 K, rising towards 1 but never exceeding it. The apparent activation energy is the k-weighted average (kBE1+kCE2)/(kB+kC), which must lie between 50 and 70.