For the reaction 2N2O5 -> 4NO2 + O2, which set of equalities correctly gives the rate of reaction?

-(1)/(2)(d[N2O5])/(dt)=(1)/(4)(d[NO2])/(dt)=(d[O2])/(dt)

-(d[N2O5])/(dt)=(d[NO2])/(dt)=(d[O2])/(dt)

-(1)/(2)(d[N2O5])/(dt)=(1)/(4)(d[NO2])/(dt)=(d[O2])/(dt)

-2(d[N2O5])/(dt)=4(d[NO2])/(dt)=(d[O2])/(dt)

-(1)/(2)(d[N2O5])/(dt)=4(d[NO2])/(dt)=(d[O2])/(dt)

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NEET levelSingle correct optionDifficulty 1 of 3ck169

For the reaction $2 N X_{2} O X_{5} 4 NO X_{2} + O X_{2}$ , which set of equalities correctly gives the rate of reaction?

A $- \frac{d [ N X _{2} O X _{5} ]}{d t} = \frac{d [ NO X _{2} ]}{d t} = \frac{d [ O X _{2} ]}{d t}$
B $- \frac{1}{2} \frac{d [ N X _{2} O X _{5} ]}{d t} = \frac{1}{4} \frac{d [ NO X _{2} ]}{d t} = \frac{d [ O X _{2} ]}{d t}$
C $- 2 \frac{d [ N X _{2} O X _{5} ]}{d t} = 4 \frac{d [ NO X _{2} ]}{d t} = \frac{d [ O X _{2} ]}{d t}$
D $- \frac{1}{2} \frac{d [ N X _{2} O X _{5} ]}{d t} = 4 \frac{d [ NO X _{2} ]}{d t} = \frac{d [ O X _{2} ]}{d t}$

Answer: B

The rate of reaction is the rate of change of each concentration divided by its stoichiometric coefficient, with a minus sign for reactants. Here the coefficients are 2, 4 and 1, so the rate equals

- \frac{1}{2} d [N X_{2} O X_{5}] / d t = \frac{1}{4} d [NO X_{2}] / d t = d [O X_{2}] / d t

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For the reaction 2NX2​OX5​​4NOX2​+OX2​, which set of equalities correctly gives the rate of reaction?

Answer: B

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For the reaction $2 N X_{2} O X_{5} 4 NO X_{2} + O X_{2}$ , which set of equalities correctly gives the rate of reaction?