Answer: B
From the 300 to 310 K data, Ea/R=1/300−1/310ln3=10217 K. Then lnk300k320=10217(0.0002083)=2.129, giving 8.40. This is a little below the rule-of-thumb value 9, because the 20 K interval is not exactly twice the 10 K interval in terms of 1/T.