JEE Advanced levelSingle correct optionDifficulty 3 of 3ck147
The first-order decomposition 2NX2OX5(g)4NOX2(g)+OX2(g) starts with pure NX2OX5 at 200 mmHg in a rigid vessel (ignore dimerisation of NOX2). The total pressure is 290 mmHg after 20 min. The half-life in minutes (with ln2=0.693) is
A38.9
B54.4
C85.3
D23.2
Answer: A
If p of NX2OX5 reacts, Pt=(P0−p)+2p+p/2=P0+1.5p. So p=(290−200)/1.5=60 mmHg and pA=140 mmHg. k=201ln140200=0.0178min−1, t1/2=0.693/k=38.9 min.