JEE Advanced levelSingle correct optionDifficulty 3 of 3ck102
For Aproducts a plot of log(rate) against log[A] (rate in molL−1min−1, [A] in molL−1) is a straight line of slope 2.00 and intercept −1.699. Take log2=0.301. The order and rate constant are
Aorder 2, k=1.7Lmol−1min−1
Border 1, k=2.0×10−2min−1
Corder 2, k=2.0×10−2Lmol−1min−1
Dorder 2, k=50Lmol−1min−1
Answer: C
Rate =k[A]n gives log(rate)=logk+nlog[A], so the slope is the order, n=2, and the intercept is logk=−1.699=−2+0.301=log(2×10−2). Hence k=2.0×10−2Lmol−1min−1. Reading the intercept as k itself, or using 10+1.699, gives the wrong options.