Answer: A, C, D
Experiments 1 and 2: doubling [A] doubles the rate (order 1 in A). Experiments 1 and 3: doubling [B] quadruples the rate (order 2 in B), so rate =k[A][B]2 and k=5.0×10−4/(0.10×0.102)=0.50 L2 mol−2 s−1. At 0.30 M each, rate =0.50×0.303=1.35×10−2.