For A + B -> products the following initial rate data were obtained. Experiment 1: [A] = 0.10, [B] = 0.10, initial rate = 2.0x10^-3. Experiment 2: [A] = 0.20, [B] = 0.10, initial rate = 8.0x10^-3. Experiment 3: [A] = 0.20, [B] = 0.20, initial rate = 8.0x10^-3 (concentrations in mol L^-1, rates in mol L^-1 s^-1). The rate law is

JEE Main levelSingle correct optionDifficulty 2 of 3ck081

For $A + B products$ the following initial rate data were obtained. Experiment 1: $[A] = 0.10$ , $[B] = 0.10$ , initial rate $= 2.0 \times 1 0^{- 3}$ . Experiment 2: $[A] = 0.20$ , $[B] = 0.10$ , initial rate $= 8.0 \times 1 0^{- 3}$ . Experiment 3: $[A] = 0.20$ , $[B] = 0.20$ , initial rate $= 8.0 \times 1 0^{- 3}$ (concentrations in $mol L^{- 1}$ , rates in $mol L^{- 1} s^{- 1}$ ). The rate law is

Experiments 1 and 2:

[A]

doubles with

[B]

fixed and the rate rises four-fold, so the order in

A

is 2. Experiments 2 and 3:

[B]

doubles with

[A]

fixed and the rate is unchanged, so the order in

B

is 0. Hence rate

= k [A]^{2}