JEE Main levelSingle correct optionDifficulty 2 of 3ck067
For 2AP with −d[A]/dt=k[A]2, k=0.020Lmol−1s−1 and [A]0=0.50molL−1. The time needed for 75% of A to react is
A100s
B200s
C139s
D300s
Answer: D
For second order 1/[A]−1/[A]0=kt. At 75% completion [A]=[A]0/4, so kt=3/[A]0 and t=3/(0.020×0.50)=300s. This is three times the half-life 1/(k[A]0)=100s, not two.