Answer: A, B, C
For first order t1/2=0.693/k, independent of [A]0, and k has the unit of inverse time. For 99.9% completion t=ln1000/k=6.908/k, which is 6.908/0.693=9.97≈10 half-lives. The expression [A]0/2k is the half-life of a zero order reaction.