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NEET levelSingle correct optionDifficulty 1 of 3ck005

For a reaction with rate law rate $= k [A]^{2} [B]$ , the concentration of $A$ is tripled and that of $B$ is halved. The rate changes by a factor of

A $1.5$
B4.5
C $9$
D $3$

Answer: B

New rate/old rate

= 3^{2} \times \frac{1}{2} = 9 \times 0.5 = 4.5

. The factor for A is squared because A is second order, while B contributes its factor to the first power.

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