A reaction has Delta H deg = +60 kJ/mol and Delta S deg = +150 J mol^-1 K^-1, both independent of temperature (R = 8.314 J mol^-1 K^-1). Select the correct statements.

ln K plotted against 1/T is a straight line with negative slope

Adding an inert gas at constant temperature changes the value of K

JEE Advanced levelOne or more correct optionsDifficulty 3 of 3ce220

A reaction has $Δ H^{\circ} = + 60 kJ/mol$ and $Δ S^{\circ} = + 150 J mo l^{- 1} K^{- 1}$ , both independent of temperature ( $R = 8.314 J mo l^{- 1} K^{- 1}$ ). Select the correct statements.

ln K = - Δ H / RT + Δ S / R

is linear in

1/ T

with slope

- Δ H / R < 0

(A true).

K = 1

when

T = Δ H /Δ S = 60000/150 = 400

K (B true). At

450

ln K = 2.005

, so

K = 7.42 > 1

(C true).

K

depends only on temperature (D false).