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JEE Main levelNumerical answerDifficulty 2 of 3ce195

For a reaction, $Δ H = + 98.0 kJ/mol$ and $Δ S = + 240 J mo l^{- 1} K^{- 1}$ (both assumed independent of temperature). At what temperature (in K, nearest integer) does the equilibrium constant become exactly 1?

Numerical answer type, answer in K, tolerance 0.5.

Answer: 408 K

K = 1

means

Δ G^{\circ} = 0 = Δ H - T Δ S

, so

T = Δ H /Δ S = 98000/240 = 408.33

K, i.e. 408 K.

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