For $CH X_{4} (g) + H X_{2} O (g) CO (g) + 3 H X_{2} (g)$ , $K_{p} = 0.080 at m^{2}$ at a certain temperature. Using $1 atm = 101.3 kPa$ , express $K_{p}$ in $kP a^{2}$ (nearest integer).

Numerical answer type, answer in kPa^2, tolerance 1.

Answer: 821 kPa^2

Δ n = 4 - 2 = + 2

, so

K_{p}

has units

pressur e^{2}

K_{p} = 0.080 \times (101.3)^{2} = 0.080 \times 10261.69 = 820.9 kP a^{2}