JEE Advanced levelNumerical answerDifficulty 3 of 3ce038
1.0 mol of HX2 and 2.0 mol of IX2 are heated in a 1.0 L closed vessel where HX2(g)+IX2(g)2HI(g) has Kc=54. Calculate the amount of HI at equilibrium, in mol, to two decimal places.
Numerical answer type, answer in mol, tolerance 0.005.
Answer: 1.88 mol
Let x mol of HX2 react: (2x)2=54(1−x)(2−x), i.e. 50x2−162x+108=0 (all values in mol/L as V=1.0 L). The root with x<1 is x=0.9385. Hence n(HI)=2x=1.877 mol.