In a 1 L vessel at equilibrium, [SO2] = 0.20 M, [O2] = 0.10 M and [SO3] = 0.40 M for 2SO2(g) + O2(g) 2SO3(g). The value of K_c (in L mol^-1) is

JEE Main levelSingle correct optionDifficulty 2 of 3ce012

In a 1 L vessel at equilibrium, $[SO X_{2}] = 0.20 M$ , $[O X_{2}] = 0.10 M$ and $[SO X_{3}] = 0.40 M$ for $2 SO X_{2} (g) + O X_{2} (g) 2 SO X_{3} (g)$ . The value of $K_{c}$ (in $L mo l^{- 1}$ ) is

K_{c} = [SO X_{3}]^{2} / ([SO X_{2}]^{2} [O X_{2}]) = (0.40)^{2} / ((0.20)^{2} (0.10)) = 40.0

. Not squaring the concentrations gives 20.0, and inverting the expression gives 0.025.