JEE Advanced levelNumerical answerDifficulty 3 of 3cb110
Using MO theory, find the sum of the bond orders of OX2X−, OX2X2−, NX2X+ and CX2X−. Give the answer to one decimal place.
Numerical answer type, tolerance 0.05.
Answer: 7.5
Valence electrons are 13, 14, 9 and 9. OX2X−: (8−5)/2=1.5. OX2X2−: (8−6)/2=1. NX2X+ and CX2X− each have 7 bonding and 2 antibonding electrons: (7−2)/2=2.5. Sum =1.5+1+2.5+2.5=7.5.